Question

(18x^5 + 6x^4 − 12x^3) ÷ 6x^2

Answer 1

\[\large (18x^5 + 6x^4 - 12x^3) \div 6x^2\]


\[\large \frac{18x^5 + 6x^4 - 12x^3}{6x^2}\]


\[\large \frac{6x^2(3x^3 + x^2 - 2x)}{6x^2}\]


I'll let you finish up

Answer 2

I have no idea how to do this
@jim_thompson5910

Answer 3

Ok here's how you do the full problem


\[\large (18x^5 + 6x^4 - 12x^3) \div 6x^2\]


\[\large \frac{18x^5 + 6x^4 - 12x^3}{6x^2}\]


\[\large \frac{6x^2(3x^3 + x^2 - 2x)}{6x^2}\]


\[\large \frac{\cancel{6x^2}(3x^3 + x^2 - 2x)}{\cancel{6x^2}}\]


\[\large \frac{1(3x^3 + x^2 - 2x)}{1}\]


\[\large \frac{3x^3 + x^2 - 2x}{1}\]


\[\large 3x^3 + x^2 - 2x\]

Answer 4

hopefully that helps

Answer 5

the idea is to factor out the 6x^2 since that's in the denominator

then you cancel out the common terms and simplify

Answer 6

Thanks so much

Answer 7

np

Answer 8

Can it be maybe be simplified further, though?

Answer 9

As in 3x^3 + x^2 - 2x = x(3x^2 + x - 2)
= x(3x - 2)(x+1)

Answer 10

you could factor, but it's pretty much simplified at this point

Answer 11

Yes, sorry, I meant maybe it could be factored.