Check my answer please. I think the answer is D. Is that correct or not? Identify the vertex and the axis of symmetry of the graph of the function y=3(x+2)^2-3. A. Vertex: (2,-3), Axis of symmetry: x=2 B. Vertex: (-2,-3), Axis of symmetry: x=-2 C. Vertex: (2,3), Axis of symmetry: x= 2 D. Vertex: (-2, 3), Axis of symmetry: x=-2
http://highaimsggb.pbworks.com/f/1281101981/Parabola%20-%20Vertex%20Form.png
\(\bf y=3(x+2)^2-3\implies y=3(x-(-2))^2+(-3)\)
Did you find the vertex? It will be (h, k), from @jdoe0001
From the pic he gave.
Thanx you guys (: It seems like the answer is A, but How do I tell about the axis of symmetry?
axis of symmetry is just the x-coordinate of the vertex. A isn't correct.
Jdoe, I don't understand the second comment, why did you turn the h, into -2?
Because the regular form is y = a(x - h)^2 + k and the vertex is (h, k) (notice the h changes sign) y = 3(x + 2)^2 - 3 so the vertex is (-2, -3)
And the x-coordinate of that vertex, is your axis of symmetry
So it's B ?
Yep :)
Thank you (:
welcome :)
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