Question

Help please

Answer 1

you add the like terms

Answer 2

okay let me do it and you tell me if im right okay :)

Answer 3

ok ^^

Answer 4

is one C

Answer 5

yup

Answer 6

is 2 d i have other questions 5 have 8 more

Answer 7

yup go ahead

Answer 8

Here is 3 and 4

Answer 9

4 is correct what u get for 3?

Answer 10

I dont understand 3

Answer 11

@ineedhelpnow08 you there?

Answer 12

its basically like number 2

Answer 13

here let me rewrite it for you

Answer 14

\[(3x ^{2} +x-3)-(x ^{2}-5x+1)\]

Answer 15

okay let me try

Answer 16

is is c? here are the next 2

Answer 17

no its not c (-3-1=-4)

Answer 18

so its d and for 6 i know its a or d and for 5 i dont get it.

Answer 19

6 is a

Answer 20

the area of a rectangle is length x width
so basically you multiply the expression

Answer 21

b?

Answer 22

here are 7 and 8

Answer 23

nope its a (3x+5)(x-2)=3x^2-x-10

Answer 24

ohh okay I get it

Answer 25

for 8 is it a?

Answer 26

7 is wrong\[(3x-5)^{2} =
(3x-5)\times(3x-5)=9x ^{2}-15x-15x+25=9x ^{2}-30x+25\]

Answer 27

is 8 a ?

Answer 28

8 is d
\[(2x ^{2}+3x-6)\times(x-1)=\]
\[2x ^{3}+3x ^{2}-6x-2x ^{2}-3x+6= \]
\[2x ^{3}+x ^{2}-9x\]

Answer 29

\[2x ^{3}+x ^{2}-9x+6\]

Answer 30

okay here is 9 and 10 9 i think its b and 10 im not sure but i think its subtraction

Answer 31

am I corrrect?

Answer 32

um i dont see number 9 and 10

Answer 33

now? lol

Answer 34

@ineedhelpnow08 is 9 b and is 10 subtraction?

Answer 35

actually i got c for 9... how did you do it?
also 10 is addition since it wanted the total cost

Answer 36

i multiplied the first equation to the second equation

Answer 37

thanks :)

Answer 38

no problem... do you need help with 9?

Answer 39

no I get it :)

Answer 40

ah ok :)