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Use algebra to evaluate the limit. limh→ 0[(2(5 + h)^2 − 50)/h]
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Well, do it! Expand (5+h)^2 and you'll nearly be done.
Expand the binomial in the numerator, simplify, and then you'll be able to just substitute in the h=0.
I got -10 and it said it was incorrect.
Yeah, that's not it. Can you show your work? what did you get when you expanded the numerator?
(2(5 + h)^2 − 50) = ?
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i got 20h+2h^2
good. Now divide that by h. What do you get?
20+2h
Right! So you have: [(2(5 + h)^2 − 50)/h] =20+2h Now let h->0. What do you get?
Oh, i see what i did! Thank you!
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You're welcome! :)
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