Two parallel rails with negligible resistance are 10.0 cm apart and are connected by a 5.00 ohm resistor.The circuit also contains 2 metal rods having resistance of 10.0 ohm and 15.0 ohm sliding along the rails.The rods are pulled away from the resistor at constant speeds 8.00 m/s and 4.00 m/s respectively.A uniform MF of 0.010 T is applied perpendicular to the plane of the rails.Determine the current in the 5.00 ohm resistor!

Question

dls · Answer

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dls · Answer

@Mashy

dls · Answer

Maybe both rods will induce BLV each in opposite directions so
e (net)=| BL(V1-V2)|

dls · Answer

hello?anyone

anonymous · Answer

yea correct...in both circuits there will be an emf.. and therfore a current..  calculate that emf.. and the current..

anonymous · Answer

something is wrong with the site.. difficult to hit the post button!

dls · Answer

what will be the R ? in i=e/R?

dls · Answer

@Mashy

anonymous · Answer

you have take them in series..  for each circuit!

anonymous · Answer

in the left one it would be 5+ 10 and the right one 5 + 15 i believe!

dls · Answer

o.O

fifciol · Answer

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Use Faraday's law and the current in 5 ohm's resistor will be the sum of currents I1 and I2. I get I in 5 ohm's resistor = Bl(v1/15-v2/20) But I'm not sure if this is correct