Question

The polynomial (x-a)^3+b is zero at x=1 and when divided by x the remainder is -7. Find the values of a and b.

Answer 1

?=-7

Answer 2

are you sure that's when divided by " x " ?

Answer 3

what is the the number that divided by x to get -7

Answer 4

there's no number, its just divided by x to get -7

Answer 5

you mean (x-3)^3+4/x = -7 ???

Answer 6

dean12

Answer 7

I think so

Answer 8

no no you cant get -7

Answer 9

so it's not possible to solve?

Answer 10

no the problem is on the div try to make sure of this Ex

Answer 11

i have 2 equations according information above :
(1 - a)^3 + b = 0 ... (1)
(x - a)^3 + b = -7 ... (2)
there are 3 variables a,b, and x, actually we need 3 equations to solve them

Answer 12

how do we get a third equation?

Answer 13

maybe subtract the 1st to 2nd equa, then cancel the b's... but not sure it works

Answer 14

(x - a)^3 + b = -7 i cant understand this

Answer 15

that's remainder thorem, @AntarAzri

Answer 16

@RadEn what do you mean f(x) = -7 for example ?

Answer 17

when u solve it, u wil get the value of x at which f(x) leaves a remainder of -7

Answer 18

if that convinces u.. :)

Answer 19

@ganeshie8 can you type it on the equation tool below

Answer 20

type what

Answer 21

what you are saying use the equation tool

Answer 22

i sure there is a missing number after word " when divided by x " ...
that should says " when divided by (x + or - a) " , with a constant

Answer 23

there isn't

Answer 24

maybe take a screenshot and post the original question.. that may help

Answer 25

I've attached the question

Answer 26

there will be multiple values i think

Answer 27

multiple values are possible most likely, but do you know of any way to solve it

Answer 28

cool, then we can try... let me think a bit
i was thinking u looking for an uniq value of a and b

Answer 29

The polynomial (x-a)^3+b is zero at x=1

(1-a)^3+b = 0 ----------(1)

Answer 30

when divided by x the remainder is -7

when divided by x-0 the remainder is -7

that means f(0) = -7

(0-a)^3+b = 0 ---------(2)

Answer 31

2 equations, 2 unknowns
u can solve them

Answer 32

from (2), b = -a^3
put this value in (1)

(1-a)^3 - a^3 = 0

u wil get a quadratic in a, solve it

Answer 33

I got the answer, thanks for your help!

Answer 34

np :) you must have gotten 2 value for a since its a quadratic