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Algebra 10 Online
OpenStudy (anonymous):

f(x)=1/√(x^2-4) g(x)=√(x^2-9) Find the domain of each of the following combinations: f(x)+g(x) f(x)/g(x)

OpenStudy (anonymous):

I managed to find the domains for f(x) and g(x). Now where do i go from there?

ganeshie8 (ganeshie8):

take the most restrictive of f(x) and g(x)

ganeshie8 (ganeshie8):

wat did u get for domains of f(x) and g(x) ? :)

OpenStudy (anonymous):

f(x)= x<−2,x>2 (−∞,−2) U (2,∞) g(x)= x≤−3,x≥3 (−∞,−3]U[3,∞)

ganeshie8 (ganeshie8):

yes, so which one is more restrictive ?

ganeshie8 (ganeshie8):

domain of g(x) is more restrictive right ? so domain for the combination wud be the domain of g(x)

OpenStudy (anonymous):

yeah i though g(x) also. this means it applies to both correct?

ganeshie8 (ganeshie8):

also, for f(x)/g(x), g(x) =/= 0

ganeshie8 (ganeshie8):

it applies to both, but for f(x)/g(x) u need add the constraint g(x) =/= 0

ganeshie8 (ganeshie8):

that gives domain of f(x)/g(x) as x < -3, x > 3

ganeshie8 (ganeshie8):

domain of f(x) + g(x) will be same as domain of g(x) : x <= -3, x >= 3

ganeshie8 (ganeshie8):

does that confuse u

OpenStudy (anonymous):

this whole thing does but i think i got the hang of this problem

ganeshie8 (ganeshie8):

good :) in simple words :- 1) the domain of f(x) + g(x) must satisfy both f(x) and g(x) 2) the domain of f(x)/g(x) must satisfy both f(x) and g(x), AND g(x) \(\ne\) 0

OpenStudy (anonymous):

Yeah. Thanks for breaking it down for me.

ganeshie8 (ganeshie8):

np :)

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