Calculate the pH in the titration
25.0 ml of 0.1M acetic acid by sodium hydroxide after the addition to the acid solution of 10ml of 0.1M NaOH
How should we start?
you're titrating a weak acid, so find \([H_3O^+]\) after neutralization. Take into account the conjugate base of acetic acid and how that influences the pH.
\[CH_3COOH+NaOH \rightleftharpoons CH_3COONa+H_2O\] Acetic acid is acid, Water is conjugate acid NaOH is base, Sodium acetate is conjugate base
Should we use an ICE table for this?
\[CH_3COOH+NaOH \rightleftharpoons CH_3COONa+H_2O \] I 2.5x10-3 1x10-3 0 C -1x10-3 -1x10-3 +1x10-3 E 1.5x10-3 0 1x10-3 [CH3COOH]=0.1M [CH3COONa]=0.02857M Hmm
The problem with applying Henderson - Hasselbalch equation is they did not give the Ka for this titration... :\
i'm sure they're expecting you to look up the Ka in your book, or elsewhere. I don't think it's possible otherwise
Yep, that's exactly what you are supposed to do.
I got pH=4.58
Correct!
Awesome thanks :)
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