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find the perimeter bound by r = 2sinθ and r=1 plese help be used by integration.
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you probably have to use chain rule, to derive 2*f(x) and f'(x)
best to start with a drawing...
first of all, I assume you mean 'find the area bounded by r = 2sinθ and r=1 , correct?
yes.
so what does the graph of r=1 look like?
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actually it is a polar coordinate problem in Length of arc..
|dw:1380378101610:dw|
oh, then that's a bit different...
and then draw \(r=\sin(2\theta)\) on that...
|dw:1380378237179:dw|
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r = 2sinθ is what is given not r = sin(2θ)
ok but why did you shade in the area? I thought we wanted arc length. Which arc length?
|dw:1380378461330:dw|
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