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OpenStudy (anonymous):
Find S (long integral sign) (x^1/2 - 4) (x^-1/2 - 1)dx.
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hartnn (hartnn):
can you foil ?
(a+b)(c+d) = ... ?
OpenStudy (tkhunny):
Entirely algebraic. What's stopping you from multiplying the two factors and having only exponents you can deal with?
OpenStudy (anonymous):
I can't do the x^1/2 times by the x^-1/2.....what would I get?
hartnn (hartnn):
yeah, after you multiply u get three terms,
and you use the fact that integral x^n dx = x^{n+1}/(n+1) +c
hartnn (hartnn):
the
\(\huge {x}^{1/2}\times x^{-1/2}=x^{1/2+(-1/2)}=...? \)
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OpenStudy (anonymous):
Yeah lol
OpenStudy (tkhunny):
For \(a\ne0\), we have \(a\cdot\dfrac{1}{a} = a^{1}\cdot a^{-1} = a^{1-1} = a^{0} = 1\)
OpenStudy (anonymous):
Would that give me x^0 which would make x^1 or just 1?
hartnn (hartnn):
x^0 =1 yes
OpenStudy (anonymous):
I got it thanks
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hartnn (hartnn):
cool :)
welcome ^_^
hartnn (hartnn):
and WELCOME to OpenStudy :D
OpenStudy (tkhunny):
You DO have to stay away from x = 0.
OpenStudy (anonymous):
Thanks... Got it @tkhunny and thanks @hartnn. I'll be on here a lot more now haha :D
hartnn (hartnn):
Glad to hear that :)
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