i dont know how i am supposed to graph this so i can find the domain range and y intercept can someone help me? Suppose you manage a juice factory. One of your machines fills 850 bottles per minute. Each day it takes 30 min to get the machine started after an hour for maintenance. • Graph the number of bottles filled as a function of time that the machine runs. • Find the domain, range, and y-intercept of the graph. Interpret these numbers. • Write an equation for your graph.
@Coolsector @ganeshie8 @divagirl421 @Hero help?
@ChipperJay* @chmvijay @CoolKatt16
@***[ISURU]***
ok. so to graph it, instead of using x and y, use "t" (time) for the horizontal line (the one usually designated x) and "b" (bottles) for the verticle line (the one usually designated y) now, for the first 90 minutes you get zero for everything, since you're told that (Each day it takes 30 minutes to get the machine started after an hour of maintenance). so, number you're graph from say 0 to 100, by ones. from 0 to 90 each "b" value is 0, so you get a line going from (0,0) to (90,0) now once you get above 90 you can fill 850 bottles per minute. so number the "b" values by multiples of 850, so you get: 850, 1700, 2550, 3400, 4250, etc. so you get points at (91,850), (92,1700), (93,2550), (94,3400), (95,4250), etc. this means your graph will have two lines connected. one from (0,0) to (90,0) that just runs along the "b" line, and then a slanted line going from (90,0) to (95,4250) and beyond. * for part (2) the domain, which is all numbers representing time you can put in and still get an answer, is going to be: 0 and beyond. (you can't have negative time) the range is all numbers you can get out, which is also 0 and beyond. (you can't produce a negative amount of bottles). the y-intercept is the point where the graph touches the y-axis (which were calling "b" for bottles). this is the point (0,0). the y-intercept simply means, that when you just get started you haven't produced any bottles yet, which makes sense. (3) here's the function in notation: f(t) = 0 if t <= 90 and f(t) = 850(t-90) if t > 90
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