Question

What is the domain of sqrt(1-x^2) ?

Answer 1

Well, that depends. :D

Answer 2

Are you referring to a complex worth function?

Answer 3

ok the question assigned is what is the domain of f(x,y) = sqrt(1-x^2) - sqrt(1-y^2)

Answer 4

I'm a bit rusty on this stuff

Answer 5

all reals where 1-(x^2) >= 0 because you can't have a nevgative in the square root . simplified to 1 >= x^2 you get x > or = +- 1

Answer 6

You can have negative in the root.

Answer 7

Simply use the definition that i=sqrt(-1).
(Which is why you need to know if the function is complex/real.

Answer 8

Oh gotcha, It's a real function not complex

Answer 9

Then just state what is required;
1-x^2>=0 and 1-y^2>=0

Answer 10

Do you know where to go from here?

Answer 11

Ya I do, that was a useful response, thanks

Answer 12

No problem man, I can tell you're here to learn! :)
Just don't forget that sqrt(x^2) is generally not the same thing as x.

Answer 13

But instead sqrt(x^2)=|x|

Answer 14

So i was right.. i know what imaginary numbers are, Noliec. thanks

Answer 15

cool, thanks

Answer 16

You were breaking the Code of Conduct on openstudy quite straight forward, footballa.