Solve the following system using the substitution method.

x + 3y = -5
5x + 6y = -19

negative three, negative two-thirds
negative three, two-thirds
three, negative two-thirds
three, two-thirds

Question

Solve the following system using the substitution method.

x + 3y = -5
5x + 6y = -19
 		
	negative three, negative two-thirds
	negative three, two-thirds
	three, negative two-thirds
	three, two-thirds

tkhunny · Answer

That first x looks compelling.  x = -5 - 3y
Substitute this value for x into the 2nd equation.

anonymous · Answer

x + 3y = -5 
i.e.  x= -3y-5
Substituting  x= -3y-5 in 5x + 6y = -19 we find 
5(-3y-5) + 6y = -19
i.e. -15y -25 +6y =-19
i.e. 6y-15y  =25-19
i.e. -9y  =6
i.e. y  =6/(-9)
i.e. y  =2/(-3)

Therefore 
x = -3*2/(-3)-5
x = 2-5
x = -3

thus {x, y} ={-3, 2/(-3)} is the required solution set of the given system of linear equations.

anonymous · Answer

@acriley3

anonymous · Answer

So what would the ordered pair be?

anonymous · Answer

I mean the answer

anonymous · Answer

Out of the ones I put up there

anonymous · Answer

B?

tkhunny · Answer

A and C have y = -2/3 - You must pick between those.