OpenStudy (anonymous):

Implicit differentiation sin(x+y)=xy

4 years ago
OpenStudy (anonymous):

Im stuck where I have $(1+\frac{ dy }{ dx })-x \frac{ dy }{ dx }=y+x \frac{ dy }{ dx }$

4 years ago
OpenStudy (goformit100):

sin(x+y)=xy or, cos(x+y) . [ 1+ dy/dx ] = x dy/dx + y

4 years ago
OpenStudy (anonymous):

Ya thats what I ment

4 years ago
OpenStudy (anonymous):

I dont know what to do from here exactly in cos(x+y) [1+dy/dx]= x dy/dx + y

4 years ago
OpenStudy (goformit100):

or, cos(x+y) + cos(x+y) dy/dx = x dy/dx + y or, cos(x+y) dy/dx - x dy/dx = y - cos(x+y) or, dy/dx {cos(x+y) - x} = y - cos(x+y) or, dy/dx = [ y - cos(x+y) ] / [ cos(x+y) - x ].................. Ans.

4 years ago
OpenStudy (anonymous):

The last one

4 years ago
OpenStudy (goformit100):

differentiation of sin(x+y) is :- cos(x+y) . [ 1+ dy/dx ]

4 years ago
OpenStudy (anonymous):

right

4 years ago
OpenStudy (goformit100):

Yes the Last one [ y - cos(x+y) ] / [ cos(x+y) - x ] is the answer :)

4 years ago
OpenStudy (anonymous):

Thanks for the help :)

4 years ago