Mathematics
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OpenStudy (anonymous):
If f(x) = log3 (x + 1), what is f^−1(2)?
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hartnn (hartnn):
can you find f^(-1) (x) first ?
hartnn (hartnn):
y=log_3 (x+1)
isolate x from here
OpenStudy (anonymous):
so would it be log3*1 = x
hartnn (hartnn):
what ?
do u know \(if, \log_ab=c \implies a^c=b \)
?
OpenStudy (anonymous):
no
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hartnn (hartnn):
now you know,
so from that what about
\(\log_3(x+1)=y \implies ???\)
OpenStudy (anonymous):
c^y = ( x + 1 ) .... i just took the formula you gave me and plugged in
hartnn (hartnn):
you mean \(\huge 3^y=x+1\)
instead of c ?
OpenStudy (anonymous):
oh ok
hartnn (hartnn):
and f^(-1) (2) means the value of y is given to be 2
so you just need 'x' from
\(\huge 3^2=x+1\)
got this ? any doubts till here ?
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OpenStudy (anonymous):
1
8
10
27
these are my answer choices
hartnn (hartnn):
what is 3^2 =... ?
OpenStudy (anonymous):
9
hartnn (hartnn):
yes,
so can u find x from
9=x+1 ??
OpenStudy (anonymous):
x=8
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hartnn (hartnn):
correct! :)
OpenStudy (anonymous):
Given the function f(x) = 0.3(4)^x, what is the value of f^−1(6)?
will i do the same for this
hartnn (hartnn):
6 = 0.3 4^x
yes! same :)
OpenStudy (anonymous):
do i multiply 0.3 and 4
hartnn (hartnn):
nopes,
6/0.3 = 4^x
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OpenStudy (anonymous):
i keep getting 1.03
hartnn (hartnn):
what are the choices ?
OpenStudy (anonymous):
0.360
1.242
2.161
2.312
hartnn (hartnn):
with 4^x = 6/0.3
using a calculator, i get
2.161
OpenStudy (anonymous):
what do i put in first
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hartnn (hartnn):
put where ?
OpenStudy (anonymous):
the answer was correct thank you
OpenStudy (anonymous):
& i have the TI 84plus calculator ..i'm still trying to work it lol
hartnn (hartnn):
its ok :)
and welcome ^_^
OpenStudy (anonymous):
would you like t help me on another assignment
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hartnn (hartnn):
ask your questions in a new post,
so that even if i am unavailable, others can help you :)
OpenStudy (anonymous):
it's up