Let c be any constant number. Which of the following will always be perpendicular to −3x + y = 2?

y = 3x + c

y = 1/3x + c

y = −3x + c

y = -1/3x + c

Question

Let c be any constant number. Which of the following will always be perpendicular to −3x + y = 2?

 y = 3x + c

 y = 1/3x + c

 y = −3x + c

 y = -1/3x + c

anonymous · Answer

The first thing to do is put −3x + y = 2 into y=mx+b form. From there, perpendicular lines are just the negative inverse of the slope. ie -1/m

anonymous · Answer

In general, the system, $S$ of:
$$S=\left\{\eqalign{
&y=ax+b \
&y=-\frac{1}{a}x+c \
}\right.$$
Will always intersect perpendicularly.

anonymous · Answer

For any numbers b or c

anonymous · Answer

Or "a" haha

anonymous · Answer

So the general formula for an
y perpendicular line is:
$$y=mx+b$$
$$y=-\frac{ 1 }{ m }+b$$

anonymous · Answer

okay thank you both :)

anonymous · Answer

so the answer is the second one right?

anonymous · Answer

@KeithAfasCalcLover   @Mathis1  ^^^^

anonymous · Answer

just kidding it would be the llast answer right?

anonymous · Answer

Yep! Fourth

anonymous · Answer

Thank you! :)