Is the inequality always, sometimes or never true? 9(x+2) > 9(x-3) answer is 2>3 and i said it's never true, right? 2. 6x-13 < 6(x-2) answer is 6x-13 < 6x-12 my answer is sometimes 3. -6(2x-10) + 12x less than or equal to 180. im stuck.
If you did the first and second inequality correctly then you are right. A way to check for number 2 is by putting in a negative number, zero, and positive number for x and see what happens. So basically for number 3 you have \[-6(2x-10)+12x \le180\] Solve for x and see.
Oh okay so for number 2 it would be 13<2 which is never true and as for 3, it's 60. so it would be 60 less than or greater than 180.. which is always true.
Right? Idk.
I have a strong feeling the first one is never true. the second one is never true and the third one is always true.
Well the first one is \[9x+18>9x-27\]So it is saying a number plus 18 is more than the same number minus 27. Do you think that is true? Second one \[6x-13<6x-12\] is saying that a number minus 13 is smaller that the number minus 12. What do you think? Third one\[-6(2x-10)_12x \le180\]\[-12x+60+12x \le180\]\[60\le180\]What do you think?
1. Sometimes true. 2. true. 3. true. :3 .-.
Is that the right answer you checked? As I said, use negative,positive and zero numbers as x to check. Use 1,-1 and 0 for simplicity. When I replaces x in number 1 with 1, I get 27>-26. When I use -1 I get 9>-36. When 0, 18>-27 Are those all true?
So 1. Would be true, yes. 2. True and 3rd is true. Unless I keep doing the math wrong.
Well....3 ends up saying 60 is less than or equal to 180. I think that's always true unless it's considered sometimes true for some reason. Do you have the answer for this so I can check?
SO 1. is 18 > -27 , right? and 2 is 13 < 12, right?
Any positive number is always larger than a negative number. And you might want to check for number 2 again. I did not get 13<12. You might want to watch out for signs. :)
wait wait. it's both negative. -13<-12 right?
Yup.
OH!!! Hahaha. So it's true!
Yup :) Good job
YAY! 30 problems finished THANK YOU SO SO MUCH.
You're very welcome.
Join our real-time social learning platform and learn together with your friends!