Find the distance between P and Q.
P(sqrt 7,0); Q(0,3)

Question

Find the distance between P and Q. 
P(sqrt 7,0); Q(0,3)

debbieg · Answer

The distance between any two points is:

$\large d=\sqrt{(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}$

Can you use that with your points to compute the distance?

anonymous · Answer

@DebbieG yes but the $$\sqrt{7}$$ is confusing me

anonymous · Answer

do i change it to decimal points? @DebbieG

debbieg · Answer

Nooo.... :) don't be afraid of the square root. :) Plug it into the formula, and watch what happens! It will be very easily taken care of.

debbieg · Answer

What will you get for the difference of the x's? And then you will SQUARE that. It all works out.

anonymous · Answer

@DebbieG can you pleaseee help me solve this my answers are all wrong :(

anonymous · Answer

What's your question

debbieg · Answer

Let's start by substituting your points in to the part that goes under the square root:

$\large (x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}$

You have the points :$\large (\sqrt{7},0),(0,3)$.

 so those are your $\large (x_{1},y_{1}),(x_{2},y_{2})$.

Can you plug them in? Tell me what you get inside each parenthesis:

$\large (x_{1}-x_{2})=??$
$\large (y_{1}-y_{2})=??$