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State the vertical asymptote of the rational function. f(x) =(x-6)(x+6)/(x^2-9)
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if we grab the denominator, and solve for "x", what do we get? \(\bf f(x) =\cfrac{(x-6)(x+6)}{x^2-9}\\ \quad \\ \quad \\ x^2-9=0\implies x = \square?\)
factor the denominator and then find the let each binomial factor equal zero the solutions will be the vertical asymptotes
and set to 0, should have added =)
When you see "vertical asymptote", think "that's where the denominator equals 0. First see if anything cancels...then see what value of x will make the denominator 0.
3 and -3 right?
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The question asks for the asymptote. Make sure you phrase your answer correctly. Answer: x = 3 and x = -3
i got it, thank you!!
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