Which of the following is a solution to the equation log 4 x + log 4 (x – 3) = 1 ?
Do you mean, \[\log_4x+\log_4(x-3)=1\]
yes
Then use the properties of logarithms, \[\log_ax+\log_ay=\log_a(xy)\]\[\log_ax=1\Rightarrow x=a\] \[\log_4 x+\log_4(x-3)=1\Rightarrow \log_4\left(x(x-3)\right)=1\Rightarrow x(x-3)=4\] And solve for x. Do you understand it and know how to solve it?
not really
ohhh i get it now
thanks
;), only to check it, the only (good) solution is 4.
1 over the square root of 8 = 4(m + 3)
can you help with this too
Do you mean, \[\frac{1}{\sqrt{8}}=4(m+3)\]
yes
i taught it was 9/4 but its not
Then, it is a matter of solve for m, \[(m+3)=\frac{1}{4\sqrt{8}}\Rightarrow m=\frac{1}{4\sqrt{8}}-3\]
You can "simplify" a little of express it in various forms, \[m=\frac{1-24\sqrt{2}}{8\sqrt{2}}=\frac{\sqrt{2}-48}{16}\]
or express it, I mean.
-2.911
Yes ;).
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