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How do you find the tangent line to the graph of "f" at the given point in: f(x)= x^2 + 1
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Is this a calculus question?
Yes
find derivative.
it'd be 2x
I don't understand how you got 2x??
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replace x wiht your equation. later on you'll find a different way of doing so.
Yes but what about the equation for the tangent line??
To find the slope at x, take the derivative: f'(x) = 2x To find the equation of the tangent line, use point-slope form, with (x₁, y₁) = (t, f(t)), and m = 2t: y - (t² + 1) = 2(x - t) y - t² - 1 = 2x - 2t y = 2x + (t² - 2t + 1)
Where t is the given x value.
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