Question

What power is dissipated by the R2=0.5 Ohm resistor in the figure (below) if R1=1.0 Ohm?

Answer 1

Solve the following equations:
\[V_{R_2}\left( \frac{ 2 }{ R_1}+\frac{ 1 }{ R_2 } \right)-\frac{ 12 }{ R_1 }+\frac{ 15 }{ R_1 }=0 \rightarrow V_{R_2}=\frac{ -3R_2 }{ R_1+2R_2 }=\frac{- 3·0.5 }{ 1+2·0.5 }=-0.75 \text{ Volts}\]\[P_{R_2}=\frac{ V_{R_2}^2 }{ R_2 }=\frac{ 0.75^2 }{ 0.5 }=1.125 \text{ W}\]

Answer 2

thank you!