Question

6x^2 +11x -10

Answer 1

factorise

Answer 2

(3x-5)(2x-6) ?

Answer 3

6x^2 -28x -30

Answer 4

The 3x & 2x parts are right

Answer 5

(3x+15)(2x-4)

Answer 6

5& 6 don't multiply to 10

Answer 7

Nevermind, I misunderstood your question.

Answer 8

15 & 4 don't multiply to 10. What c n you multiply to get 10

Answer 9

10 and 1

Answer 10

add to make 11

Answer 11

True but it doesn't work with the 2x &3x. Tr another way to get 10

Answer 12

5 and 2

Answer 13

What you could do though: is you know that constant term is negative, meaning one constant term in your factored expression has to be negative.
(3x+a)(2x-b)
Which is 6x^2-3bx+2ax-ab

Answer 14

You must FOIL your selection to see that al parts fit

Answer 15

Yes. 5 & 2. Which goes where

Answer 16

3x +5 2x-2

Answer 17

FOIL. That. Does it work

Answer 18

no

Answer 19

Switch them

Answer 20

now it works

Answer 21

is there a quick way of doing it?

Answer 22

What do u have

Answer 23

(3x-2)(2x+5)

Answer 24

Yes

Answer 25

what is the method?

Answer 26

Not really. You learn by trial & error at first. It gets easier as you progress.

Answer 27

That is what I call trial & error using the FOIL method.

Answer 28

trial and error is not a good thing

Answer 29

It's not a bad thing it's thinking through a process using what u know.

Answer 30

It undermines real knowledge of the problem. In some cases it's unavoidable though, which is a shame.

Answer 31

It's one way to get a feel for the process. With work, the process becomes clearer.

Answer 32

In my district, we call that discovery learning, constructing meaning & knowledge through observation & trials.

Answer 33

i cant do that in an exam

Answer 34

it takes too much time

Answer 35

That's why yo practice through homework U could use the quadratic formula

Answer 36

You can get to the point that you can do those problems almost automatically
Is this HS or college math for u

Answer 37

The quadratic formula is the worst thing to ever happen the modern generation of math.

Answer 38

Always complete the square instead.

Answer 39

Good idea..forgot about that.

Answer 40

what would the working out look like for completing the square

Answer 41

The expression you have written above is a bit unclear; always be 100% structured doing math and never take any shortcuts for granted.

Answer 42

Have u learned that yet

Answer 43

But basically, if you have an expression such as (x+a)*(x+b) where a and b can be any numbers there is. You have (x+a)*(x+b)=x^2+bx+ax+ab; from this alone you can most times realize your solution to a problem.

Answer 44

In your case for example, you had a 6 in front of the x^2 term; how would you get this to apply to the rule above? Simply multiply everything by 6!
6*(x+a)*(x+b)=6*(x^2+bx+ax+ab)

Answer 45

So you have 6x^2+(6a+6b)*x+ab and you wanted 6x^2+11x-10; this means that;
a*b=-10 and also that 6a+6b=11.

Answer 46

Working with variables instead of numbers are hard at first but eventually you'll become more and more used to it and improve majestically (if you keep on using variables over and over).

Answer 47

thank you