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A simple random sample of size n is drawn. The sample mean, x-bar,is found to be 17.9, and the sample standard deviation, s, is found to be 4.1. See attachment for question.
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1) 9.7, 26,1
2) 16,85, 18,95
SE = sd/sqrt(n) Se = 4,1/sqrt(61) = 0,53 Margin Error = 2*SE = 1,05
For the next one,SE = sd/sqrt(n), Then Margin Error = 2*SE So increasing n how does addect the E? i think you understand!
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4) If the sample size is 34
Se = 4,1/sqrt(34) = 0,70
Margin Error = 2*SE = 1,4
now you can see what happens if the sample size is bigger or smaller
16,5, 19,3
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the last two are very clear now. Good Luck
THANK YOU!!!
@Social the confidence intervals are supposed to be to the 2 decimal places.
16,50, 19,30
what about (a)?
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is it 9.70,26.10?
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