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Mathematics 14 Online
OpenStudy (anonymous):

A simple random sample of size n is drawn. The sample mean, x-bar,is found to be 17.9, and the sample standard deviation, s, is found to be 4.1. See attachment for question.

OpenStudy (anonymous):

OpenStudy (anonymous):

1) 9.7, 26,1

OpenStudy (anonymous):

2) 16,85, 18,95

OpenStudy (anonymous):

SE = sd/sqrt(n) Se = 4,1/sqrt(61) = 0,53 Margin Error = 2*SE = 1,05

OpenStudy (anonymous):

For the next one,SE = sd/sqrt(n), Then Margin Error = 2*SE So increasing n how does addect the E? i think you understand!

OpenStudy (anonymous):

4) If the sample size is 34

OpenStudy (anonymous):

Se = 4,1/sqrt(34) = 0,70

OpenStudy (anonymous):

Margin Error = 2*SE = 1,4

OpenStudy (anonymous):

now you can see what happens if the sample size is bigger or smaller

OpenStudy (anonymous):

16,5, 19,3

OpenStudy (anonymous):

the last two are very clear now. Good Luck

OpenStudy (anonymous):

THANK YOU!!!

OpenStudy (anonymous):

@Social the confidence intervals are supposed to be to the 2 decimal places.

OpenStudy (anonymous):

16,50, 19,30

OpenStudy (anonymous):

what about (a)?

OpenStudy (anonymous):

is it 9.70,26.10?

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