Question

PLEASE HELP ! . Calculate the mass of KI in grams required to prepare 5.00 x 102 mL of a 2.80 M solution.

Answer 1

Does M mean mol/L?

Answer 2

yes

Answer 3

\[K = 39.0983\frac{g}{mol}\]\[I = 126.90447\frac{g}{mol}\]\[5.00\times10^{2}mL\times\frac{10^{-3}L}{mL}\times\frac{2.80mol}{L}\times\frac{KIg}{mol}\]

Answer 4

yes thank you ! that set up is really helpful

Answer 5

Post the answer when you get it.

Answer 6

232.40 grams

Answer 7

Right!
\[2.32\times10^{2}g\]
three sig.figs from the 5.00 and 2.80 in the question
well done