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f(x)=((x-2)/(3)) g(x)= x^2 Find (f o g)(x).
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\[(f\circ g)(x)=f(g(x))=\frac{g(x)-2}{3}=\frac{x^2-2}{3}\]
Thank you! I just wanted to make sure I had done it right. How do I find the domain for that function?
It is a polinomy, so its domain is "all reals"
If the function was, \[\frac{2}{x^2-4}\]Then as it is a rational function, you should equate the denominator to 0, \[x^2-4=0\Rightarrow x=\pm2\] As a fraction cannot have a 0 denominator, then its domain is all reals except -2 and +2.
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