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Find the area inside the cardioid r=1+cos(theta) for 0 is greater than or equal to theta, which is greater than or equal to 2pi.
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@timo86m .....do you know how to do this? :D
have you tried this in Polar?
what do u mean?
here you go: http://en.wikipedia.org/wiki/Polar_coordinate_system#Integral_calculus_.28area.29 \[\rightarrow \frac{1}{2} \int\limits_0^{2\pi}(1+\cos \theta)^{2} d \theta\]
((3pi(x))/(2))
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now what?
?? im lost, what is 3pi/2 for
value of the integral...
oh sorry i was using wolfram and it gave decimal anyway, that is the area
my online homework thing just crashed so i cant check the answer....hold please:) lol
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okay so its 4.71239 :D
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