How do you find an equation for a line that is tangent to the graph of y=e^x and goes through the origin?

Question

wolfe8 · Answer

What does the tangent line have in common with the graph at the point they touch? Hint: It is the same as the derivative of the graph. Given that, and at least one point that the tangent goes through, you can construct a line equation. Can you recall what that is?

anonymous · Answer

I tried to solve by finding the derivative, which I thought was e^x, and using that as the slope in the equation for the line tangent to that graph that goes through the origin, and got $$y=xe ^{x}$$ but that answer's supposed to be y=xe. Why?

wolfe8 · Answer

Hmm I'm not sure.

wolfe8 · Answer

Maybe the answer it wrong?