integral from 0 to 2 of (5-((4-x^2)^(1/2))
did you try to substitute \(x=2\sin u\) ?
dx= ... ? 4-x^2 =... ?
Yup. I got to the integral of 4cos^2x, but am a little stuck on this part...
(5-2cos u)(2 cos u) du how did u just get 4 cos^2 u ?
i get 10 cos u -4cos^2 u du
hah, my bad, I pulled out the 5 as a separate integral
but where you are is where I'm stuck
cool so, cos^2 u write that in terms of cos2u, can u ?
know the formulas for cos 2x ?
I don't...there's a formula?
I don't understand how I can write cos^2u in terms of cos(2u)
yup \(\large \cos2x=\cos^2x-\sin^2x=2\cos^2x-1=1-2\sin^2x\) heard of them ?
so, from cos2x = 2 cos^2x-1 could you isolate cos^2 x???
You mean from the 4?
i just mean, whether you can isolate cos^2x from cos2x = 2 cos^2x-1 ?
I don't know, the concept is foreign to me,
cos2x = 2 cos^2x-1 so, cos^2 x = (cos 2x+1)/2 just simple algebra
\(\int 4\cos^2x dx = 4\int\dfrac{\cos2x+1}{2}dx \) and can you integrate cos 2x and 1 ?
ahh okay I got it!
I'm good from here, was just confused on that step!
thanks !
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