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the unit digit in the product (122)^173 is
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\[ 2^1=2\\ 2^2=4\\ 2^3=8\\ 2^4=16 (6)\\ 2^5=32 (2)\\ 2^6=64 (4)\\ 2^7=128 (8)\\ 2^8=256 (6)\\ 2^9=512 (2)\\ 2^{10}=1024 (4)\\ \]The pattern here is \(2,4,8, 6,2,4,8,6,\ldots\)
Figure out the remainder of \(173\).
The remainder when dividing by \(4\).
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8
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8 is the remainder ah
No, the remainder after dividing by 4. It should be between 0, 1, 2, and 3.
why divied by 4
It's the remainder.
Starting at 173 We can remove 100 since it's divisible by 100 73 We can remove 40 33 We can remove 20 13 We can remove 12 1 So the remainder is 1
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\(2^1=2\) so the unit digit will be 2.
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