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Mathematics 14 Online
OpenStudy (anonymous):

thermal energy

OpenStudy (anonymous):

estimate the thermal energy lost by a cup (250 grams) of a coffee while cooling from 200 degree F to room temperature 72 degree F

OpenStudy (anonymous):

@wio can you help me out with formula up here

OpenStudy (anonymous):

Isn't it some equation with specific heat and such?

OpenStudy (anonymous):

ya but there are two equations, i m confused which one to use

OpenStudy (anonymous):

Show me the equations.

OpenStudy (anonymous):

\[K_{avg} (per molecule) = \frac{ 3 }{ 2 } k _{B} T\] or \[\frac{ 3 }{ 2 } N k_{B} T\]

OpenStudy (anonymous):

And \(k_B\) is specific heat?

OpenStudy (anonymous):

it is Boltzmann constant

OpenStudy (anonymous):

Well, \(N\) and \(k_B\) don't change so: \[ E_2-E_1=\Delta E=\frac 32Nk_BT_2 - \frac 32Nk_BT_2 =\frac 32Nk_B( T_2-T_1)=\frac 32Nk_B\Delta T \]

OpenStudy (anonymous):

So you need to find \(\Delta T\) and \(N\)

OpenStudy (anonymous):

But I'm not even sure how you'd find \(N\) since I don't know particles per gram for coffee.

OpenStudy (anonymous):

ohk so i think forst formula

OpenStudy (anonymous):

Unless you assume it is just water.

OpenStudy (anonymous):

it is cofee

OpenStudy (anonymous):

most likely they just calculate the coffe as if it was water

OpenStudy (anonymous):

oh do you have any idea about that N thing up there

OpenStudy (anonymous):

concentrations of coffee vary. if they don't give additional detail, there is not one solution

OpenStudy (anonymous):

ohk ty

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