Help me with find dy/dx for the function : y=(3x+6)^1/2
chain rule it is, know whats chain rule ?
yes
so did u try this ? whats your attempt ?
i know what chain rule is, but im not sure if this is a chain rule
take log on both sides ..and do diffrentiaton
u know whats the derivative of sqrt x ?
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hartnn no shkrina oookkayy, let me understand this first...
know the derivative of x^n ?
guys there r many ways to to do .. simple way sgoes by applying log ...
other way?
definition of simple is different for everyone ^_^
we are discussing 2 methods, my chain rule method, and her log method
the chain rule...umm, the step solution?
for chain rule, you should be able to calculate the derivative of sqrt x...
or x^(1/2) using the formula for x^n
(3x+6)^1/2 = (3x+6)^-2 is it wrong?
yes, its incorrect
(3x+6)^1/2 = ??
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let 3x+6 = f(x) so, \(\huge \dfrac{d}{dx}\sqrt{f(x)}=\dfrac{1}{2\sqrt{f(x)}}\dfrac{d}{dx}f(x)\) this is chain rule, where i have used the fact that d/dx (sqrt x) = 1/ 2sqrt x
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