Question

Write an equation for the circle that satisfies the given set of conditions.

1. Center (8, -3), radius 6
2. Center (5, -6), radius 4
3. Center (-5, 2), Passes through (-9, 6)
4. Endpoints of a diameter at (6, 6) and (10, 12)

Answer 1

1.(x-8)^2+(y+3)^2=6^2

Answer 2

(x1,y1)is the centre and r is the radius

Answer 3

(x-8)^2 +(y+3)^2 =36

Answer 4

(x-8)^2 +(y+3)^2 =36

Answer 5

That didnt help me what so ever

Answer 6

hey lets do from scratch

Answer 7

Thank you!

Answer 8

1. Center (8, -3), radius 6

Answer 9

alright

Answer 10

we use this :-
equation of circle wid center \((h, k)\) and radius \(r\) :-

\((x-h)^2 + (y-k)^2 = r^2\)

Answer 11

equation of circle wid center (8, -3) and radius 6 :-

\((x-8)^2 + (y--3)^2 = 6^2\)

\((x-8)^2 + (y+3)^2 = 36\)

Answer 12

okay. That makes sense

Answer 13

cool :)

Answer 14

try next q for urself :) il correct if u go wrong, give it a try

Answer 15

can u ? :)

Answer 16

\[(x-5)^{2}+(y+6)^{2}=4^{2}\]

\[(x-5)^{2}+(y+6)^{2}=16\]

Answer 17

sorry my computer was bugging out for a second

Answer 18

What equation do i use for the other two problems

Answer 19

ping once u r back :)

Answer 20

i am