Question

Limits,

http://screencast.com/t/tGHGzNJm

Answer 1

Remember that dividing by a fraction is the same as multiplying by the inverse - so dividing by -1/x^2 is the same as multiplying by -x^2.

So, the \[\huge \frac{ \frac{ 3 }{ x^2 } }{ \frac{ -1 }{x^2 } } = \frac{ 3 }{ x^2 }*(-x^2)\]

Answer 2

But my fraction is different

Answer 3

that's part of the fraction... it was easier to write. The same principle applies.

Answer 4

\[\huge \frac{ \frac{ 1 }{ 1-3/x }*\frac{ 3 }{ x^2 } }{ \frac{ -1 }{x^2 } } = \frac{ 1 }{ 1-3/x } * \frac{ 3 }{ x^2 }*(-x^2)\]

Answer 5

the x^2's cancel leaving\[\LARGE \frac{ 1 }{ 1-3/x } * \frac{ 3 }{ x^2 }*(-x^2) = \frac{ -3 }{1-3/x }\]

Answer 6

ty

Answer 7

=)

Answer 8

No prob :) hope it made sense!