Question

Let f(x) = 1/{\sqrt{6x^{2}+6}}. Find f'(x).

Answer 1

Sorry, it should be this way,
\[f(x)=(6x^2+6)^{-1/2} \]
\[f'(x)=\frac{-1}{2}(6x^2+6)^{-3/2}(12x)=-6x(6x^2+6)^{-3/2}\]

Answer 2

so the 1 on top doesn't matter?

Answer 3

No, because,
\[\frac{1}{x}=x^{-1}\]
You can always use this, and differentiate like a power.

Answer 4

okay thanks again haha :)

Answer 5

You're welcome ;).