lnx-ln3=2
Here's a rule of logs: \(\ln(ab) = \ln a - \ln b\)
\( \ln x- \ln 3 = 2 \) \(\ln \dfrac{x}{3} = 2 \) Now use the definition of log.
Definition of log: \(\log_b x = y\) means \(b^y = x\)
is says here use one to one property to solve for x?
What is one to one property?
if loga(m) = loga(n) then m=n
Here there is log only on the left side. The right side is simply 2.
then x = 5?
No. Are you sure the problem up on top is the correct problem? Was it supposed to be ln x - ln 3 = ln 2 ? Did you leave out the ln with the 2 on the right side?
yep the problem is correct, my bad it says solve log. ew. algebriacally
*log. eq.
If the problem is correct, then let's continue where we left off. We need to use the definition of log to continue. Remember that ln is log base e.
We were here: \(\ln \dfrac{x}{3} = 2\) This means the same as: \(\log_e \dfrac{x}{3} = 2\) Using the definition, we get: \(e^2 = \dfrac{x}{3} \) Now multiply both sides by 3.
x=3e^2??
Correct.
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