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Algebra 19 Online
OpenStudy (anonymous):

lnx-ln3=2

OpenStudy (mathstudent55):

Here's a rule of logs: \(\ln(ab) = \ln a - \ln b\)

OpenStudy (mathstudent55):

\( \ln x- \ln 3 = 2 \) \(\ln \dfrac{x}{3} = 2 \) Now use the definition of log.

OpenStudy (mathstudent55):

Definition of log: \(\log_b x = y\) means \(b^y = x\)

OpenStudy (anonymous):

is says here use one to one property to solve for x?

OpenStudy (mathstudent55):

What is one to one property?

OpenStudy (anonymous):

if loga(m) = loga(n) then m=n

OpenStudy (mathstudent55):

Here there is log only on the left side. The right side is simply 2.

OpenStudy (anonymous):

then x = 5?

OpenStudy (mathstudent55):

No. Are you sure the problem up on top is the correct problem? Was it supposed to be ln x - ln 3 = ln 2 ? Did you leave out the ln with the 2 on the right side?

OpenStudy (anonymous):

yep the problem is correct, my bad it says solve log. ew. algebriacally

OpenStudy (anonymous):

*log. eq.

OpenStudy (mathstudent55):

If the problem is correct, then let's continue where we left off. We need to use the definition of log to continue. Remember that ln is log base e.

OpenStudy (mathstudent55):

We were here: \(\ln \dfrac{x}{3} = 2\) This means the same as: \(\log_e \dfrac{x}{3} = 2\) Using the definition, we get: \(e^2 = \dfrac{x}{3} \) Now multiply both sides by 3.

OpenStudy (anonymous):

x=3e^2??

OpenStudy (mathstudent55):

Correct.

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