a jet ascends at a 10 degree angle with an airspeed of 550 mph. How fast is the altitude of the jet increasing? If the sun is directly overhead, how fast is the shadow of the jet moving on the ground? calculus question using related rates

Question

wolf1728 · Answer

sine (10°) = x / 550
.17365 = x / 550
x = 550 * .17365
x = 95.5075 mph (rate at which altitude is increasing.

anonymous · Answer

So i do not have to find dy/dx of anything?

wolf1728 · Answer

Shadow of the Jet
cosine 10° = adjacent / 550
.98481 = adj / 550
adj = .98481 * 550
adj = 542 mph = speed of airplane's shadow

wolf1728 · Answer

No, to me it seems you don't need calculus at all.