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Mathematics 15 Online
OpenStudy (anonymous):

How do you take the derivative of (x-5)/x^2 -25)?

OpenStudy (anonymous):

quotient rule!

OpenStudy (anonymous):

it's going to be [(1) (x^2 - 25) - (2x)(x-5) ]/ (x^2 - 25)^2

OpenStudy (anonymous):

So what do you have to do to get that?

OpenStudy (anonymous):

well the general formula for the quotient rule, where (u/v)' = (u'v - uv') / v^2

OpenStudy (anonymous):

How do you take a derivative when there is a square root in the equation?

OpenStudy (anonymous):

Like: The square root of (X-5) -3/x-4

OpenStudy (anonymous):

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