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OpenStudy (anonymous):
Find the derivative
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OpenStudy (anonymous):
Find f'(4)
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
@thomaster
OpenStudy (anonymous):
@Yttrium @Jack1 any ideas? i tried getting the slope and that did'nt work
OpenStudy (jack1):
have an idea...maybe...
derivative of a line is the instantaneous gradient at that point
so at x=4, gradient = 1.2 = 0.5
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OpenStudy (jack1):
sorry that was 1/2 not 1.2
OpenStudy (anonymous):
it is correct but how did you get that?
OpenStudy (jack1):
gradient = y2 -y1/ x2-x1
OpenStudy (anonymous):
yeah i understand that..but what are the points
OpenStudy (jack1):
gradient also = f'(x)
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OpenStudy (anonymous):
I think the hardest part was finding the points to plug in for the x and y because they werent exact more like decimals
OpenStudy (jack1):
so y2 = 2
y1 = 1
x2 = 5
x1 = 3
OpenStudy (rsadhvika):
you can see that , between x = 3 and x = 5, the line is going 1 grid up as u move 2 grids right
OpenStudy (jack1):
|dw:1380631118750:dw|
OpenStudy (rsadhvika):
u can write the equation within that interval for that line as :-
\(\large f(x) = \frac{1}{2}x + k\)
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OpenStudy (anonymous):
|dw:1380631211797:dw|
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