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Mathematics 13 Online
OpenStudy (anonymous):

Find the derivative

OpenStudy (anonymous):

Find f'(4)

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@thomaster

OpenStudy (anonymous):

@Yttrium @Jack1 any ideas? i tried getting the slope and that did'nt work

OpenStudy (jack1):

have an idea...maybe... derivative of a line is the instantaneous gradient at that point so at x=4, gradient = 1.2 = 0.5

OpenStudy (jack1):

sorry that was 1/2 not 1.2

OpenStudy (anonymous):

it is correct but how did you get that?

OpenStudy (jack1):

gradient = y2 -y1/ x2-x1

OpenStudy (anonymous):

yeah i understand that..but what are the points

OpenStudy (jack1):

gradient also = f'(x)

OpenStudy (anonymous):

I think the hardest part was finding the points to plug in for the x and y because they werent exact more like decimals

OpenStudy (jack1):

so y2 = 2 y1 = 1 x2 = 5 x1 = 3

OpenStudy (rsadhvika):

you can see that , between x = 3 and x = 5, the line is going 1 grid up as u move 2 grids right

OpenStudy (jack1):

|dw:1380631118750:dw|

OpenStudy (rsadhvika):

u can write the equation within that interval for that line as :- \(\large f(x) = \frac{1}{2}x + k\)

OpenStudy (anonymous):

|dw:1380631211797:dw|

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