You are trying to compare the Fahrenheit and Celsius scales and you have two examples: Temperature A is 50 degrees Celsius and 122 degrees Fahrenheit. Temperature B is 100 degrees Celsius and 212 degrees Fahrenheit. What graph models the relationship between the Fahrenheit and Celsius scales? What is an equation of the line in slope-intercept form?

Question

You are trying to compare the Fahrenheit and Celsius scales and you have two examples:  Temperature A is 50 degrees Celsius and 122 degrees Fahrenheit.  Temperature B is 100 degrees Celsius and 212 degrees Fahrenheit.  What graph models the relationship between the Fahrenheit and Celsius scales?  What is an equation of the line in slope-intercept form?

anonymous · Answer

attachment

unklerhaukus · Answer

which of those options have the point (55,122)?

anonymous · Answer

None of them?

unklerhaukus · Answer

two of the options have the point (55,122)

anonymous · Answer

2 & 3

opcode · Answer

$$m = \frac{y2-y1}{x2-x1}$$
You have two points insert then into that formula.

opcode · Answer

(50, 122) 
(100, 212)

$$m = \frac{212-122}{100-50}$$
$$\frac{9}{5} = \frac{212-122}{100-50}$$

mathstudent55 · Answer

Use the points (50, 122) and (100, 212) to find the equation of the line that passes through them.

$y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1} (x - x_1) $

$y - 122 = \dfrac{212 - 122}{100 - 50} (x - 50) $

$y - 122 = \dfrac{90}{50} (x - 50) $

$y - 122 = \dfrac{90}{50}x - \dfrac{90}{50} \cdot 50 $

$y - 122 = \dfrac{9}{5}x - 90 $

$y = \dfrac{9}{5}x + 32 $

Since we are using x and y instead of C and F, just replace x with C and y with F.