Construct a truth table for the given statement: HELP!!!! ~(p<->~q)
what means <-> ? :)
<---> The imply eachother?
THEY*
you are right "means that P and Q are equivalent. So the double implication is true if P and Q are both true or if P and Q are both false; otherwise, the double implication is false" atachment: p<->q
I understand that, but it is the drawing the actual truth table for this is what I don't get
I will first do the ~q and align the results accordingly: p | ~q | p<->~q ---------------------- T | ~T=F | F T | ~F=T | T F | ~T=F | T F | ~F=T | F I just used the opposite truth value for each q, compared with before
SO then would ~(p<--> q) be T, F, F, T?
Oops I mean ~(p<-->~q)
yep exactly :) also,you're not supposed to put ~q in a truth table, it makes evaluating easier but in the end: p | q | p<->~q ---------------------- T | T | F T | F | T F | T | T F | F | F the table should not make the inversion, only the statement should ;-)
We have ~q listed in our homeworktruth table.. So I am really confused
really? I guess the rules aren't that strict then........
So then would ~(p <--> ~q) be the opposite of p<--> ~q?
yes T F F T
Instead of F T T F, would it be T F F T?
great, thanks! I hope this stuf gets easier. I enjoy numbers WAY better.
stuff*
yeah you get better with time and you're welcome
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