The mean percentage of a population of people eating out at least once a week is 57%, with a standard deviation of 3.5%. Assume that a sample size of 40 people was surveyed from the population an infinite number of times. In which interval will 95% of the sample means occur?

Question

amistre64 · Answer

assuming an empirical rule:  and a modified sigma divided by the sqrt(n) ...

amistre64 · Answer

1 = .0035/sqrt(40) so, .57 +- 2

amistre64 · Answer

.035/sqrt(40) .. got a little zero happy on that lol

anonymous · Answer

A.55.89% – 58.11% 
B. 56.45% – 57.55%
C. 56.54% – 57.46%
D. 56.07% – 57.93% 
E. 55.34% – 58.669%

amistre64 · Answer

yep, that fits one of them

anonymous · Answer

Which one though im still confused....Even my math teacher couldnt figure out the answer...

amistre64 · Answer

1 = .035/sqrt(40) .57 - 2 to .57 + 2

amistre64 · Answer

.57 - 2(.035)/sqrt(40)  to  .57 + 2(.035)/sqrt(40)

anonymous · Answer

? Ive been working on this for hours and we found nothing what is the answer is it "B"

amistre64 · Answer

yes, its B when you do the math of it

amistre64 · Answer

.56446  to  .57553

anonymous · Answer

Thanks so much

amistre64 · Answer

youre welcome