Question

Limit,

http://screencast.com/t/xSXV3aXEU

Answer 1

@amistre64

Answer 2

@hba

Answer 3

@dan815

Answer 4

@agent0smith

Answer 5

@Luigi0210

Answer 6

divide top and bottom by x

Answer 7

the x on top can be rewritten as x^-1 on the bottom, which is 1/x on the bottom and then it is distributed

Answer 8

and recall: sqrt(x^2) = x

Answer 9

AH ! I see how it goes

Answer 10

or another way:
\[\sqrt{x^2+x}\]
\[\sqrt{x^2(1+\frac 1x})\]
\[x\sqrt{1+\frac 1x}\]

Answer 11

hold on, I just made the division but I got 1/(sqrt(x + 1 ) + 1 which is strangely different :/

Answer 12

is there another step ?

Answer 13

@amistre64 @hartnn

Answer 14

didn't u get @amistre64 's last reply ?

Answer 15

x^2+x = x^2 (1+1/x)

Answer 16

but thats another way isn't it ? What about the "divide all by x" way ? how solve with this way and get this result ?

Answer 17

didive top n bot by x

Answer 18

\({\dfrac{\sqrt{x^2+x}}{x}}=\sqrt{\dfrac{x^2}{x^2}+\dfrac{x}{x^2}}\)