Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

please show steps

OpenStudy (anonymous):

\[\frac{ 2 }{ 3 } x - 13 = \frac{ 1 }{ 3 } (9+2x)\]

OpenStudy (mathstudent55):

The first step is to multiply both sides by 3 to get rid of the fractions. Can you do that?

OpenStudy (anonymous):

what both sides

OpenStudy (anonymous):

@mathstudent55 !!!

OpenStudy (mathstudent55):

Yes.

OpenStudy (mathstudent55):

\(\dfrac{ 2 }{ 3 } x - 13 = \dfrac{ 1 }{ 3 } (9+2x) \) \(\color{red}{3 \cdot} \left( \dfrac{ 2 }{ 3 } x - 13 \right) = \color{red}{3 \cdot} \dfrac{ 1 }{ 3 } (9+2x) \)

OpenStudy (mathstudent55):

On the left side, the 3 must be distributed. On the right side, the 3 and the 1/3 cancel out.

OpenStudy (anonymous):

i really don't get this, could you show all the steps, i somehow understand better then... in the next question ill try and solve the entire thing ;)

OpenStudy (anonymous):

@mathstudent55

OpenStudy (mathstudent55):

We were here: \( \color{red}{3 \cdot} \left( \dfrac{ 2 }{ 3 } x - 13 \right) = \color{red}{3 \cdot} \dfrac{ 1 }{ 3 } (9+2x) \) Now we distribute the 3 on the left side, and the 3 and the 1/3 on the right side cancel out: \( 3 \cdot \dfrac{ 2 }{ 3 } x - 3 \cdot 13 = 9+2x \) \(2x - 39 = 9 + 2x\) Now we subtract 2x from both sides. -39 = 9 Since we end up with a false statement, that means there is no solution to this equation.

OpenStudy (anonymous):

O.o okayy, ill try and do the next one ;/

OpenStudy (anonymous):

\[x (x-3) = (x+2)^{2}\]

OpenStudy (anonymous):

@mathstudent55 i think i have to get rid of the brackets but i don't know how to do that ;/

OpenStudy (mathstudent55):

Multiply x by x and x by -3. That is called distributing the x. On the right side, you need to square the binomial, x + 2, or multiply (x + 2)(x + 2). You can use FOIL for that,

OpenStudy (mathstudent55):

Sorry, but gtg.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!