Question

Two cars raced at a race track. The faster car traveled 20 mph faster than the slower car. In the time that the slower car traveled 165 miles, the faster car traveled 225 miles. If the speeds of the cars remained constant, how fast did the slower car travel during the race?

Answer 1

options are
1. 15 mph
2. 55 mph
3. 75 mph
4. 130 mph

Answer 2

hi,
if the speed of slower car is "x"
then the speed of faster car is (20 + x)

so both cars traveled 165 miles and 225 miles in the same time. Let's assume that time period as "t".Remember that "t" is common for the motion of both cars...

for the slower car...
distance traveled = speed * duration
165 = xt ------(1)

for the faster car ...
distance traveled = speed * duration
225 = t(x+20) ----(2)

divide (1) by (2)
165/225 = x/(x+20)
11/15 = x/(x+20)
11x + 210 = 15x
4x = 220
x = 55 mph

hope this will help ya!

Answer 3

55 mph

Answer 4

thanks jake and isuru

Answer 5

u r welcome!!