Question

Please help me!

Answer 1

Here is the question!

Answer 2

@hero wbu?

Answer 3

A couple rules to keep in mind before approaching this:
\(\sqrt{x^2} = x\) (because square and square root are inverses of each other)
\(\sqrt{ab} = \sqrt{a} \times \sqrt{b}\) (related to rules of exponents)

Now given:
\(x^2 = 160\)
Square root both sides:
\(\sqrt{x^2} = \sqrt{160}\)
\(x = \sqrt{(16)(10)}\)
\(x = \sqrt{16} \times \sqrt{10}\)

Answer 4

You can finish simplifying the result from here.

Answer 5

and when you take square root on both sides, don't forget to consider the negative root too :)
\(\sqrt{x^2} =\pm \sqrt{160}\)

Answer 6

Thanks guys idk who to give a medal to though? :/