Under what conditions does a rational function have vertical, horizontal and oblique asymptotes? use limits..
it says on my book: f(x)=g(x)/h(x) Conditions for vertical asymptote: h(x)=0 must have at least one solution s, and lim(x-> infinity) f(x)=inifinity conditions for horizontal asymptote: lim(x-> infinity) f(x)= k, where k is all real numbers --> can you just explain it further?
@agent0smith
Vertical asymptotes are when the denominator is zero - since you can't divide by zero Horizontal asymptotes are a bit more complex since they involve end behaviour... look at the highest powers of x on the numerator and denominator to find the horiz. asymptotes. If the numerators highest power is smaller than the denominators, eg 3x^3 and 4x^5, the asymptote is y=0. If the numerator and denominator have the same highest power, the asymptote is the the ratio of the coefficients... eg 3x^2 and 5x^2... y=3/5 Oblique or slant asymptotes come from the numerator having a greater highest power than the denominator... you have to use long division to find the slant asymptote.
I'd explain using limits but i don't have time...
ok thanks!, i will just read what you wrote..
i already know that from grade 11, i just don't know how to explain it using limits..
Horizontal asymptotes lim x => inf, y => (the value of the horiz. asymptote) verticals: lim x => (a value that gives a denominator of zero), y => + or - infinity etc, but i gotta go.
ok, thanks for ur time(^_^)
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