Question

Find an equation of the tangents to the curve y=sec x at x=(-pi/3) and (pi/4)

Answer 1

y'=?

Answer 2

derivative is sec(x)tan(x)

Answer 3

so, x = - pi/3 , y'(-pi/3) =?

Answer 4

that is where i get lost. Using the chain rule I am getting (-2sqrt3x) ((-2sqrt3pi)/3)+2. but I'm not sure.

Answer 5

(-2sqrt3x)-((2sqrt3pi)/3)+2 ... sorry

Answer 6

I am sorry. I am super dummy in teaching.

Answer 7

This is exactly what I was looking at as my answer. This is great so now if I needed to find this for pi/4. I can use same way ?

Answer 8

I think so, hehehe... good luck.

Answer 9

do you have any idea of what the graph would look like with those two tangent lines in it ?

Answer 10

you said tangent "line" , so, it's a line. that's it

Answer 11

sorry ... ok thanks. :)