Question

Divide: (7 + 4i) ÷ (2 + 3i)

Answer 1

wait i got it i was doing something wrong

Answer 2

multiply by the conjugate of the denominator, and this works because
\[(a+bi)(a-bi)=a^2+b^2\] a real number

Answer 3

the denominator you do in your head, \(2^2+3^2=4+9=13\)
the numerator you have to find \((7+4i)(2-3i)\)

Answer 4

(2-3i) i have to multi[ly to bottom and top

Answer 5

yeah

Answer 6

yeah thats what i meesed up on