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Find derivative of sin^2(x)
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think of it as \[\left(\sin(x)\right)^2\] and use the chain rule
How do i do that?
the derivative of \(x^2\) is \(2x\) and by the chain rule the derivative of \(f^2(x)\) is \[2f(x)f'(x)\]
put \(f(x)=\sin(x)\) and \(f'(x)=\cos(x)\) in the above
Well like i knew that x^2=2x and sinx=cosx but i dont know how to work the problem and write the answer
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i am fairly sure that you don't believe either \(x^2=2x\) or \(\sin(x)=\cos(x)\)
sen²x = sen x * sen x sen²x = 1 - cos²x is just a trigonometric identity
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